The value of frac{0.125+0.027}{0.5 times 0.5+ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given expression is $\frac{0.125+0.027}{0.5 	imes 0.5+0.09-0.15}$.We can write the numerator as $(0.5)^3 + (0.3)^3$ because $0.5^3 = 0.125$ a

Vedclass · Accepted Answer

$0.8$

Vedclass · Answer

(C) The given expression is $\frac{0.125+0.027}{0.5 	imes 0.5+0.09-0.15}$.We can write the numerator as $(0.5)^3 + (0.3)^3$ because $0.5^3 = 0.125$ and $0.3^3 = 0.027$.We can write the denominator as $(0.5)^2 + (0.3)^2 - (0.5)(0.3)$ because $0.5^2 = 0.25$,$0.3^2 = 0.09$,and $(0.5)(0.3) = 0.15$.Using the algebraic identity $a^3 + b^3 = (a+b)(a^2 + b^2 - ab)$,where $a = 0.5$ and $b = 0.3$,the expression becomes:$\frac{(0.5+0.3)(0.5^2 + 0.3^2 - 0.5 	imes 0.3)}{0.5^2 + 0.3^2 - 0.5 	imes 0.3}$.Canceling the common term $(0.5^2 + 0.3^2 - 0.5 	imes 0.3)$,we get $0.5 + 0.3 = 0.8$.

The value of $\frac{0.125+0.027}{0.5 \times 0.5+0.09-0.15}$ is

Similar Questions

If $a+\frac{1}{a}+2=0,$ then the value of $\left(a^{37}-\frac{1}{a^{100}}\right)$ is

The correct expression of $6.\overline{46}$ in the fractional form is

Which of the following is the $CORRECT$ rationalised form of $\frac{15}{\sqrt{5}+2} ?$

$A$ printer numbers the pages of a book starting with $1$ and uses $3189$ digits in all. How many pages does the book have?

The denominator of a fraction is $3$ more than the numerator. If the numerator as well as the denominator is increased by $4,$ the fraction becomes $\frac{4}{5}$. What was the original fraction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module