$\sum_{k=1}^{13} \frac{1}{\sin \left(\frac{\pi}{4}+\frac{(k-1) \pi}{6}\right) \sin \left(\frac{\pi}{4}+\frac{k \pi}{6}\right)}$ का मान ज्ञात कीजिए।

  • A
    $3-\sqrt{3}$
  • B
    $2(3-\sqrt{3})$
  • C
    $2(\sqrt{3}-1)$
  • D
    $2(2-\sqrt{3})$

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Similar Questions

यदि श्रेणी $\frac{4.1}{4+3.1^2+1^4}+\frac{4.2}{4+3.2^2+2^4}+\frac{4.3}{4+3.3^2+3^4}+\frac{4.4}{4+3.4^2+4^4}+\ldots$ के प्रथम $20$ पदों का योग $\frac{m}{n}$ है,जहाँ $m$ और $n$ सह-अभाज्य हैं,तो $m + n$ का मान ज्ञात कीजिए :-

$\frac{{\frac{1}{2} \cdot \frac{2}{2}}}{{{1^3}}} + \frac{{\frac{2}{2} \cdot \frac{3}{2}}}{{{1^3} + {2^3}}} + \frac{{\frac{3}{2} \cdot \frac{4}{2}}}{{{1^3} + {2^3} + {3^3}}} + \dots + n \text{ पद} =$

किसी भी $n \in N$ के लिए,$\frac{1}{2 \cdot 5} + \frac{1}{5 \cdot 8} + \ldots + \frac{1}{(3n-1)(3n+2)} = $

$1(1!) + 2(2!) + 3(3!) + \dots + n(n!) = \dots$

Difficult
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यदि $\frac{1}{2 \times 4} + \frac{1}{4 \times 6} + \frac{1}{6 \times 8} + \dots (n \text{ पद}) = \frac{k n}{4(n + 1)}$ है,तो $k$ का मान ज्ञात कीजिए।

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