The value of tan frac{pi}{8} is equal to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We know the formula $	an \frac{	heta}{2} = \frac{\sin 	heta}{1 + \cos 	heta}$.Setting $	heta = \frac{\pi}{4}$,we get $	an \frac{\pi}{8} = \f

Vedclass · Accepted Answer

$\frac{1}{\sqrt{2}+1}$

Vedclass · Answer

(C) We know the formula $	an \frac{	heta}{2} = \frac{\sin 	heta}{1 + \cos 	heta}$.Setting $	heta = \frac{\pi}{4}$,we get $	an \frac{\pi}{8} = \frac{\sin(\pi/4)}{1 + \cos(\pi/4)}$.Substituting the values $\sin(\pi/4) = \frac{1}{\sqrt{2}}$ and $\cos(\pi/4) = \frac{1}{\sqrt{2}}$,we have:$	an \frac{\pi}{8} = \frac{1/\sqrt{2}}{1 + 1/\sqrt{2}} = \frac{1/\sqrt{2}}{(\sqrt{2}+1)/\sqrt{2}} = \frac{1}{\sqrt{2}+1}$.

The value of $\tan \frac{\pi}{8}$ is equal to

Similar Questions

The value of $\cos(60^{\circ} - A) \cdot \cos A \cdot \cos(60^{\circ} + A)$ is

If $\cos A = \frac{\sqrt{3}}{2},$ then $\tan 3A = $

$\cot \theta - \tan \theta - 2 \tan 2 \theta - 4 \tan 4 \theta = $

Find $\sin \frac{x}{2}, \cos \frac{x}{2}$ and $\tan \frac{x}{2}$ given that $\cos x = -\frac{1}{3}$ and $x$ is in quadrant $III$.

If $3 \sin \theta = 2 \sin 3 \theta$ and $0 < \theta < \pi$,then $\sin \theta =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module