The value of alternating emf E in the given c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a series $LCR$ circuit,the total alternating emf $E$ is given by the phasor sum of the voltages across the resistor $(V_R)$,inductor $(V_L)$,an

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) In a series $LCR$ circuit,the total alternating emf $E$ is given by the phasor sum of the voltages across the resistor $(V_R)$,inductor $(V_L)$,and capacitor $(V_C)$.The formula is $E = \sqrt{V_R^2 + (V_L - V_C)^2}$.Given values are $V_R = 80 \, V$,$V_L = 40 \, V$,and $V_C = 100 \, V$.Substituting these values into the formula:$E = \sqrt{(80)^2 + (40 - 100)^2}$$E = \sqrt{6400 + (-60)^2}$$E = \sqrt{6400 + 3600}$$E = \sqrt{10000}$$E = 100 \, V$.

The value of alternating emf $E$ in the given circuit will be......$V$.

Similar Questions

In the given figure,the current amplitude is

When a coil is connected across a $20 \ V$ $DC$ supply,it draws a current of $5 \ A$. When it is connected across a $20 \ V, 50 \ Hz$ $AC$ supply,it draws a current of $4 \ A$. The self-inductance of the coil is .............. $mH$. (Take $\pi=3$)

In an $ac$ circuit,the current lags behind the voltage by $\pi /3$. The components in the circuit are

In an $ac$ circuit,the potential difference across an inductance and resistance joined in series are respectively $16\, V$ and $20\, V$. The total potential difference across the circuit is.......$V$

An inductance of $0.2 \ H$ and resistance of $100 \ \Omega$ are connected in series to an $AC$ of $180 \ V$,$50 \ Hz$ supply. The $RMS$ current flowing in the circuit will be . . . . . . (Take $\pi^2$ as $10$). (in $A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module