The value of current required to deposit 0.97 | vedclass

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(C) According to Faraday's law of electrolysis,the mass deposited $(m)$ is given by $m = Z 	imes I 	imes t$,where $Z$ is the $E.C.E.$,$I$ is the cur

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$0.5$

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(C) According to Faraday's law of electrolysis,the mass deposited $(m)$ is given by $m = Z 	imes I 	imes t$,where $Z$ is the $E.C.E.$,$I$ is the current,and $t$ is the time in seconds.Given: $m = 0.972 \ g$,$Z = 0.00018 \ g \ C^{-1}$,$t = 3 \ hours = 3 	imes 3600 \ s = 10800 \ s$.Rearranging the formula for current $(I)$: $I = \frac{m}{Z 	imes t}$.Substituting the values: $I = \frac{0.972}{0.00018 	imes 10800} = \frac{0.972}{1.944} = 0.5 \ A$.

The value of current required to deposit $0.972 \ g$ of chromium in $3 \ hours$ if the $E.C.E.$ of chromium is $0.00018 \ g \ C^{-1}$,is ............ $A$.

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