The value of Planck's constant is 6.63 times | vedclass

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Question

(D) The relationship between wavelength $(\lambda)$,velocity of light $(c)$,and frequency $(
u)$ is given by $\lambda = \frac{c}{
u}$.Substituting t

Vedclass · Accepted Answer

$4 	imes 10^1$

Vedclass · Answer

(D) The relationship between wavelength $(\lambda)$,velocity of light $(c)$,and frequency $(
u)$ is given by $\lambda = \frac{c}{
u}$.Substituting the given values: $\lambda = \frac{3.0 	imes 10^8 \ m \ s^{-1}}{8 	imes 10^{15} \ s^{-1}} = 0.375 	imes 10^{-7} \ m = 3.75 	imes 10^{-8} \ m$.To convert the wavelength into nanometres $(nm)$,we multiply by $10^9 \ nm/m$: $\lambda = 3.75 	imes 10^{-8} \ m 	imes 10^9 \ nm/m = 37.5 \ nm$.The value closest to $37.5 \ nm$ is $4 	imes 10^1 \ nm$.

The value of Planck's constant is $6.63 \times 10^{-34} \ J \ s$. The velocity of light is $3.0 \times 10^8 \ m \ s^{-1}$. Which value is closest to the wavelength in nanometres of a quantum of light with frequency of $8 \times 10^{15} \ s^{-1}$?

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