The value of shunt resistance,that allows onl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Resistance of galvanometer $G = 99 \Omega$. Let the main current be $I$. The current through the galvanometer is $I_g = 10 \% 	ext{ of } I

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(D) Given: Resistance of galvanometer $G = 99 \Omega$. Let the main current be $I$. The current through the galvanometer is $I_g = 10 \% 	ext{ of } I = \frac{I}{10}$. The current through the shunt resistance $S$ is $I_s = I - I_g = I - \frac{I}{10} = \frac{9I}{10}$. Since the galvanometer and shunt are in parallel,the potential difference across them is equal: $I_g \cdot G = I_s \cdot S$ $\frac{I}{10} \cdot 99 = \frac{9I}{10} \cdot S$ $99 = 9S$ $S = \frac{99}{9} = 11 \Omega$. Thus,the required shunt resistance is $11 \Omega$.

The value of shunt resistance,that allows only $10 \%$ of the main current to pass through a galvanometer of resistance $99 \Omega$,is (in $\Omega$)

Similar Questions

Give the unit of shunt.

The scale of a galvanometer is divided into $25$ equal divisions. The resistance of the galvanometer is $100 \,\Omega$. The current sensitivity of the galvanometer is $4 \times 10^{-4} \,A/div$. What resistance in $ohm$ must be connected in series to measure $2.5 \,V$?

Which of the following statements is correct?

Which of the following statements is wrong?

Define the function of the small cylinder in the construction of a galvanometer.

Vedclass Test Series

Exam Paper Generator

Online Exam Module