(C) We know that the tangent function has a period of $\pi$.Therefore, $\tan(x - n\pi) = \tan x$ for any integer $n$.Given the expression $\tan(x - 9\

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(C) We know that the tangent function has a period of $\pi$.Therefore, $\tan(x - n\pi) = \tan x$ for any integer $n$.Given the expression $\tan(x - 9\pi)$, we can write it as $\tan(x - 9\pi) = \tan x$ because $9$ is an integer.Alternatively, using the identity $\tan(\theta - n\pi) = \tan \theta$, we get $\tan(x - 9\pi) = \tan x$.

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

Medium

The value of the expression $\tan(x - 9\pi)$ is equal to:

MHT CET 2026 All MHT CET

A
$-\tan x$
B
$-\cot x$
C
$\tan x$
D
$\cot x$

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Class 11

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Trigonometrical Ratios, Functions and Identities

Subtopic

Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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The value of the expression $\tan(x - 9\pi)$ is equal to:

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If $\sin \theta = \frac{24}{25}$ and $\theta$ lies in the second quadrant,then $\sec \theta + \tan \theta = $

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Prove that:
$2 \sin ^{2} \frac{\pi}{6}+\csc ^{2} \frac{7 \pi}{6} \cos ^{2} \frac{\pi}{3}=\frac{3}{2}$