The values of current $I$ flowing in a given resistor for the corresponding values of potential difference $V$ across the resistor are given below -

$I$ (amperes)	$0.5$	$1.0$	$2.0$	$3.0$	$4.0$
$V$ (volts)	$1.6$	$3.4$	$6.7$	$10.2$	$13.2$

Plot a graph between $V$ and $I$ and calculate the resistance of that resistor.

(N/A) The plot between voltage and current is called $IV$ characteristic. The voltage is plotted on the $x-$axis and current is plotted on the $y-$axis.
The $IV$ characteristic of the given resistor is plotted in the figure.
The slope of the line gives the value of $\frac{1}{R}$ as,
Slope $= \frac{1}{R} = \frac{\Delta I}{\Delta V} = \frac{BC}{AC} = \frac{3.0 - 1.0}{10.2 - 3.4} = \frac{2.0}{6.8}$
Therefore,the resistance $R$ is,
$R = \frac{6.8}{2.0} = 3.4\, \Omega$
Thus,the resistance of the resistor is $3.4\, \Omega$.