The vapour density of a certain gas is 16. Wh | vedclass

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(B) The molar mass $(M)$ of a gas is related to its vapour density $(VD)$ by the formula: $M = 2 	imes VD$. Given $VD = 16$,so $M = 2 	imes 16 = 32

Vedclass · Accepted Answer

$5.6$

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(B) The molar mass $(M)$ of a gas is related to its vapour density $(VD)$ by the formula: $M = 2 	imes VD$. Given $VD = 16$,so $M = 2 	imes 16 = 32 \ g/mol$. The number of moles $(n)$ is calculated as: $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{8 \ g}{32 \ g/mol} = 0.25 \ mol$. At $STP$,$1 \ mol$ of an ideal gas occupies $22.4 \ dm^3$. Therefore,the volume occupied by $0.25 \ mol$ of gas is: $V = 0.25 \ mol 	imes 22.4 \ dm^3/mol = 5.6 \ dm^3$.

The vapour density of a certain gas is $16$. What is the volume occupied by $8 \ g$ of gas at $STP$ assuming ideal behaviour (in $dm^3$)?

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