The vapour pressure of pure benzene and methy | vedclass

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(C) Given that the mixture is equimolar,the mole fraction of benzene $(X_B)$ and methyl benzene $(X_M)$ in the liquid phase are both $0.5$.The partial

Vedclass · Accepted Answer

$23$

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(C) Given that the mixture is equimolar,the mole fraction of benzene $(X_B)$ and methyl benzene $(X_M)$ in the liquid phase are both $0.5$.The partial vapour pressure of methyl benzene is $P_M = X_M 	imes P^{\circ}_M = 0.5 	imes 24 \ Torr = 12 \ Torr$.The partial vapour pressure of benzene is $P_B = X_B 	imes P^{\circ}_B = 0.5 	imes 80 \ Torr = 40 \ Torr$.The total vapour pressure is $P_{	ext{total}} = P_M + P_B = 12 \ Torr + 40 \ Torr = 52 \ Torr$.The mole fraction of methyl benzene in the vapour phase $(Y_M)$ is given by $Y_M = \frac{P_M}{P_{	ext{total}}}$.$Y_M = \frac{12}{52} \approx 0.2307$.Rounding to the nearest integer as requested,$Y_M \approx 23 	imes 10^{-2}$.

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