The variation of momentum $(p)$ with time $(t)$ for one of the bodies in a two-body collision is shown in the figure. The instantaneous force is maximum corresponding to which point?

$A$ force $F = Be^{-Ct}$ acts on a particle of mass $m$,which is at rest at $t = 0$. Its terminal velocity is:

$A$ force $\vec{F} = a \hat{i} + b \hat{j} + c \hat{k}$ is acting on a body of mass $m$. The body was initially at rest at the origin. The coordinates of the body after time $t$ will be:

The magnitude of the external force acting on moving bodies can be known directly by

$A$ particle of mass $M$ originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation $F = F_{0} \left(1 - \left(\frac{t - T}{T}\right)^{2}\right)$. Where $F_{0}$ and $T$ are constants. The force acts only for the time interval $2T$. The velocity $v$ of the particle after time $2T$ is:

$A$ body of mass $1 \, kg$ is acted upon by a force $\vec F = 2\sin(3\pi t)\hat i + 3\cos(3\pi t)\hat j$. Find its position at $t = 1 \, s$ if at $t = 0$ it is at rest at the origin.