The variation of potential energy U of a syst | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The relationship between force $F$ and potential energy $U$ is given by $F = -\frac{dU}{dx}$.This means the force is the negative of the slope of

Vedclass · Accepted Answer

Vedclass · Answer

(D) The relationship between force $F$ and potential energy $U$ is given by $F = -\frac{dU}{dx}$.This means the force is the negative of the slope of the $U-x$ graph.$1$. For the interval $0 ightarrow x_1$: The slope of the $U-x$ graph is positive and constant. Therefore, the force $F = -(	ext{positive constant})$ is negative and constant.$2$. For the interval $x_1 ightarrow x_2$: The potential energy $U$ is constant, so the slope is zero. Therefore, the force $F = 0$.$3$. For the interval $x_2 ightarrow x_3$: The slope of the $U-x$ graph is negative and constant. Therefore, the force $F = -(	ext{negative constant})$ is positive and constant.Comparing this with the given options, the graph in option $D$ correctly represents a negative constant force, followed by zero force, and then a positive constant force.

The variation of potential energy $U$ of a system is shown in the figure. The force acting on the system is best represented by:

Similar Questions

If the potential energy for a particle is given by $U = K(x + y)$,where $K$ is a constant,what is the work done by the conservative force in moving a particle from $(1, 1)$ to $(2, 3)$?

In a gravitational field,if the work done along paths $1, 2$ and $3$ is ${W_1}, {W_2}$ and ${W_3}$ respectively,then:

State the principle of conservation of mechanical energy in the presence of non-conservative forces.

Is the work done by non-conservative forces always negative? Discuss.

$A$ body with mass $2\, kg$ moves in one direction in the presence of a force which is described by the potential energy graph. If the body is released from rest at $x = 2\, m$,then its speed when it crosses $x = 5\, m$ is ................ $m/s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module