The vector $x$ is perpendicular to the vectors $a=3 \hat{i}+2 \hat{j}+2 \hat{k}$ and $b=18 \hat{i}-22 \hat{j}-5 \hat{k}$,and it makes an obtuse angle with $\hat{j}$. If $|x|=14$,then $x=$

  • A
    $8 \hat{i}+12 \hat{j}+24 \hat{k}$
  • B
    $-8 \hat{i}+6 \hat{j}+24 \hat{k}$
  • C
    $8 \hat{i}-12 \hat{j}-24 \hat{k}$
  • D
    $-8 \hat{i}-12 \hat{j}+24 \hat{k}$

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