The velocity of an electromagnetic wave is pa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In an electromagnetic wave,the electric field vector $\vec E$ and the magnetic field vector $\vec B$ oscillate in phase and are perpendicular to e

Vedclass · Accepted Answer

$\vec E 	imes \vec B$

Vedclass · Answer

(B) In an electromagnetic wave,the electric field vector $\vec E$ and the magnetic field vector $\vec B$ oscillate in phase and are perpendicular to each other.According to the properties of electromagnetic waves,the direction of propagation of the wave (which is the direction of the velocity vector $\vec v$) is given by the cross product of the electric field vector and the magnetic field vector.Therefore,the velocity vector $\vec v$ is parallel to $\vec E 	imes \vec B$.This is also related to the Poynting vector $\vec S = \frac{1}{\mu_0} (\vec E 	imes \vec B)$,which represents the directional energy flux (the energy transfer per unit area per unit time) of an electromagnetic field.

The velocity of an electromagnetic wave is parallel to:

Similar Questions

Radio waves and visible light in vacuum have

In a plane electromagnetic wave,the average value of ....... is zero.

$A$ plane electromagnetic wave travels in free space along the $z$-axis. At a particular point in space, the electric field along the $x$-axis is $8.7 \ V \ m^{-1}$. The magnetic field along the $y$-axis is:

In a plane electromagnetic wave,the maximum value of the electric field component is $4.4 \ Vm^{-1}$. The intensity of the wave is nearly (in $mW \ m^{-2}$)

In an electromagnetic wave,if $\overrightarrow{E}$ is the electric field and $\overrightarrow{B}$ is the magnetic field,then the direction of propagation of the wave is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module