The volume of a cone is $9504\,cm^{3}$ and its radius is $18\,cm$. Then,its height is $\ldots\,cm$.

Volumes of two spheres are in the ratio $64: 27$. The ratio of their surface areas is

Write 'True' or 'False' and justify your answer:
An open metallic bucket is in the shape of a frustum of a cone,mounted on a hollow cylindrical base made of the same metallic sheet. The surface area of the metallic sheet used is equal to curved surface area of frustum of a cone + area of circular base + curved surface area of cylinder.

The base of a cone with radius $7\, cm$ and height $24\, cm$ is hemispherical. Find the cost of painting its surface at the rate of ₹ $2/cm^2$. (in ₹)

The radius of the base of a cylinder is $7 \, cm$. Then,the area of its base is $\dots \, cm^2$.

The base of a cone with radius $5 \, cm$ and height $12 \, cm$ is hemispherical. Find the total surface area of the article. $(\pi = 3.14)$ (in $cm^2$)