The volume of a drop of water is 0.0018 mL. | vedclass

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Question

(A) Given: Volume of one drop of water $(V)$ = $0.0018 \ mL$. Density of water $(ho)$ = $1 \ g/mL$. Mass of one drop $(m)$ = $V 	imes ho = 0.0018

Vedclass · Accepted Answer

$12.046 	imes 10^{19}$

Vedclass · Answer

(A) Given: Volume of one drop of water $(V)$ = $0.0018 \ mL$. Density of water $(ho)$ = $1 \ g/mL$. Mass of one drop $(m)$ = $V 	imes ho = 0.0018 \ mL 	imes 1 \ g/mL = 0.0018 \ g$. Moles of water in one drop = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{0.0018 \ g}{18 \ g/mol} = 10^{-4} \ mol$. Number of water molecules in one drop = $	ext{moles} 	imes N_A = 10^{-4} 	imes 6.023 	imes 10^{23} = 6.023 	imes 10^{19}$. Number of water molecules in two drops = $2 	imes 6.023 	imes 10^{19} = 12.046 	imes 10^{19}$.

The volume of a drop of water is $0.0018 \ mL$. The number of water molecules present in two drops of water at room temperature is:

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