The volume strength (in L) of 3 N H_2O_2 is a | vedclass

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(C) The normality $(N)$ of $H_2O_2$ is related to its molarity $(M)$ by the equation: $N = M 	imes n$-factor.For $H_2O_2$,the $n$-factor is $2$,so $M

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$17$

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(C) The normality $(N)$ of $H_2O_2$ is related to its molarity $(M)$ by the equation: $N = M 	imes n$-factor.For $H_2O_2$,the $n$-factor is $2$,so $M = \frac{N}{2} = \frac{3}{2} = 1.5$ $M$.The volume strength of $H_2O_2$ is given by the formula: $	ext{Volume strength} = M 	imes 11.2$.Therefore,$	ext{Volume strength} = 1.5 	imes 11.2 = 16.8$ $L$.This is approximately $17$ $L$.

The volume strength (in $L$) of $3$ $N$ $H_2O_2$ is approximately

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