The wavelength of a photon with energy 35 tex | vedclass

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(A) Given:Energy $E = 35 	ext{ keV} = 35 	imes 10^{3} 	imes 1.6 	imes 10^{-19} 	ext{ J} = 56 	imes 10^{-16} 	ext{ J}$.Using the formula for the

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$35 	imes 10^{-12} 	ext{ m}$

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(A) Given:Energy $E = 35 	ext{ keV} = 35 	imes 10^{3} 	imes 1.6 	imes 10^{-19} 	ext{ J} = 56 	imes 10^{-16} 	ext{ J}$.Using the formula for the wavelength of a photon:$E = \frac{hc}{\lambda} \implies \lambda = \frac{hc}{E}$Substituting the values:$\lambda = \frac{6.625 	imes 10^{-34} 	imes 3 	imes 10^{8}}{35 	imes 10^{3} 	imes 1.6 	imes 10^{-19}}$$\lambda = \frac{19.875 	imes 10^{-26}}{56 	imes 10^{-16}}$$\lambda \approx 0.3549 	imes 10^{-10} 	ext{ m} \approx 0.355 	imes 10^{-10} 	ext{ m} = 35.5 	imes 10^{-12} 	ext{ m}$.Rounding to the nearest provided option,the correct value is $35 	imes 10^{-12} 	ext{ m}$.

The wavelength of a photon with energy $35 \text{ keV}$ is . . . . . . .
$(h = 6.625 \times 10^{-34} \text{ J s}, c = 3 \times 10^{8} \text{ m/s}, 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J})$

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The wavelength of a photon with energy $35 \text{ keV}$ is . . . . . . .$(h = 6.625 \times 10^{-34} \text{ J s}, c = 3 \times 10^{8} \text{ m/s}, 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J})$