The wavelengths involved in the spectrum of d | vedclass

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(D) The wavelength of the spectral lines is given by the Rydberg formula:$\frac{1}{\lambda} = R_M \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$whe

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The masses of the two nuclei are different

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(D) The wavelength of the spectral lines is given by the Rydberg formula:$\frac{1}{\lambda} = R_M \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$where $R_M = \frac{R_{\infty}}{1 + \frac{m}{M}}$,$m$ is the mass of the electron,and $M$ is the mass of the nucleus.Since the mass of the deuterium nucleus $(M_D \approx 2M_H)$ is different from the mass of the hydrogen nucleus $(M_H)$,the Rydberg constant $R_M$ for deuterium is slightly different from that of hydrogen.Consequently,the wavelengths of the spectral lines for deuterium differ from those of hydrogen.Therefore,the correct option is $(d)$.

The wavelengths involved in the spectrum of deuterium $(_1^2D)$ are slightly different from that of hydrogen spectrum,because

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