The wavelengths of two notes in air are $\frac{36}{195} \,m$ and $\frac{36}{193} \,m$. Each note produces $10$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m/s$ is

An unknown frequency $x$ produces $8$ beats per second with a frequency of $250 \ Hz$ and $12$ beats per second with a $270 \ Hz$ source. Then $x$ is .... $Hz$.

Two identical straight wires are stretched so as to produce $6$ beats per second when vibrating simultaneously with tensions $T_1$ and $T_2$ respectively. On changing the tension slightly in one of them,the beat frequency remains unchanged. This will happen when (Given $\rightarrow T_1 > T_2$)

The frequency of a tuning fork is $256 \ Hz$. It will not resonate with the tuning fork of frequency (in $Hz$)

On sounding tuning fork $A$ with another tuning fork $B$ of frequency $384 \ Hz$,$6$ beats are produced per second. After loading the prongs of $A$ with some wax and then sounding it again with $B$,$4$ beats are produced per second. What is the frequency of the tuning fork $A$ in $Hz$?

If two tuning forks $A$ and $B$ are sounded together,they produce $4$ beats per second. $A$ is then slightly loaded with wax,and they produce $2$ beats when sounded again. The frequency of $A$ is $256 \ Hz$. The frequency of $B$ will be: (in $Hz$)