The weights (in kg) of 11 students are given | vedclass

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(D) To find the median,first arrange the observations in ascending order:$35, 36, 37, 37, 39, 40, 40, 40, 41, 42, 42$Here,the total number of observat

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(D) To find the median,first arrange the observations in ascending order:$35, 36, 37, 37, 39, 40, 40, 40, 41, 42, 42$Here,the total number of observations $n = 11$,which is an odd number.The formula for the median when $n$ is odd is the value of the $\left(\frac{n+1}{2}\right)$-th observation.Median $= \left(\frac{11+1}{2}\right)$-th observation$= \left(\frac{12}{2}\right)$-th observation$= 6$-th observation.Counting the $6$-th value in the ordered list: $35(1), 36(2), 37(3), 37(4), 39(5), 40(6)$.Thus,the median of the data is $40 \ kg$.

Class	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$1$	$4$	$5$	$10$	$5$	$4$	$1$

The weights (in $kg$) of $11$ students are given below:
$37, 42, 40, 39, 41, 35, 37, 36, 40, 40, 42$
Find the median of the data.

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Frequency $1$ $4$ $5$ $10$ $5$ $4$ $1$

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The weights (in $kg$) of $11$ students are given below:$37, 42, 40, 39, 41, 35, 37, 36, 40, 40, 42$Find the median of the data.