The weight of a molecule of the compound C_{6 | vedclass

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Question

(A) The molecular weight of $C_{60}H_{122}$ is calculated as: $(60 	imes 12) + (122 	imes 1) = 720 + 122 = 842 \ g/mol$. Using Avogadro's number $(N

Vedclass · Accepted Answer

$1.4 	imes 10^{-21} \ g$

Vedclass · Answer

(A) The molecular weight of $C_{60}H_{122}$ is calculated as: $(60 	imes 12) + (122 	imes 1) = 720 + 122 = 842 \ g/mol$. Using Avogadro's number $(N_A \approx 6.022 	imes 10^{23} \ mol^{-1})$,the mass of one molecule is given by: $	ext{Mass} = \frac{	ext{Molecular weight}}{N_A}$. $	ext{Mass} = \frac{842}{6.022 	imes 10^{23}} \approx 139.82 	imes 10^{-23} \ g = 1.398 	imes 10^{-21} \ g \approx 1.4 	imes 10^{-21} \ g$.

The weight of a molecule of the compound $C_{60}H_{122}$ is

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