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(A) In the given data,the highest frequency is $26,$ which corresponds to the modal class interval $201-202$.Here,the lower limit of the modal class $

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$201.7$

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(A) In the given data,the highest frequency is $26,$ which corresponds to the modal class interval $201-202$.Here,the lower limit of the modal class $l = 201$,the frequency of the modal class $f_m = 26$,the frequency of the class preceding the modal class $f_1 = 12$,the frequency of the class succeeding the modal class $f_2 = 20$,and the class width $h = 1$.The formula for the mode is:$	ext{Mode} = l + \left( \frac{f_m - f_1}{2f_m - f_1 - f_2} ight) 	imes h$Substituting the values:$	ext{Mode} = 201 + \left( \frac{26 - 12}{2 	imes 26 - 12 - 20} ight) 	imes 1$$= 201 + \left( \frac{14}{52 - 32} ight)$$= 201 + \frac{14}{20} = 201 + 0.7 = 201.7 \, g$.Hence,the modal weight is $201.7 \, g$.

Weight (in $g$)	Number of packets
$200-201$	$12$
$201-202$	$26$
$202-203$	$20$
$203-204$	$9$
$204-205$	$2$
$205-206$	$1$

Class	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$
Frequency	$8$	$12$	$27$	$x$	$55$	$37$	$y$

Number of pages written per day	$16-18$	$19-21$	$22-24$	$25-27$	$28-30$
Number of days	$1$	$3$	$4$	$9$	$13$

The weight of coffee in $70$ packets is shown in the following table:

Weight (in $g$) Number of packets

$200-201$ $12$

$201-202$ $26$

$202-203$ $20$

$203-204$ $9$

$204-205$ $2$

$205-206$ $1$

Determine the modal weight (in $g$).

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The weight of coffee in $70$ packets is shown in the following table: Weight (in $g$) Number of packets $200-201$ $12$ $201-202$ $26$ $202-203$ $20$ $203-204$ $9$ $204-205$ $2$ $205-206$ $1$ Determine the modal weight (in $g$).