The weight of oxalic acid that will be required to prepare a $1000 \ mL$ $(N / 20)$ solution is

  • A
    $126 / 100 \ g$
  • B
    $63 / 40 \ g$
  • C
    $63 / 20 \ g$
  • D
    $126 / 20 \ g$

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With $63 \ g$ of oxalic acid,how many litres of $\frac{N}{10}$ solution can be prepared?

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The primary standard solution for the estimation of $Na_2S_2O_3$ is:

$10 \ cm^{3}$ of $0.1 \ N$ monobasic acid requires $15 \ cm^{3}$ of sodium hydroxide solution whose normality is: (in $N$)

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