The weights of two iron balls are 3.5 text{ k | vedclass

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(A) To find the percentage weight of the first ball with respect to the second ball,we use the formula:$	ext{Percentage} = \left( \frac{	ext{Weight

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$46 \frac{2}{3} \%$

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(A) To find the percentage weight of the first ball with respect to the second ball,we use the formula:$	ext{Percentage} = \left( \frac{	ext{Weight of first ball}}{	ext{Weight of second ball}} ight) 	imes 100$Substituting the given values:$	ext{Percentage} = \left( \frac{3.5}{7.5} ight) 	imes 100$$= \left( \frac{35}{75} ight) 	imes 100$$= \left( \frac{7}{15} ight) 	imes 100$$= \frac{700}{15} = \frac{140}{3} = 46 \frac{2}{3} \%$

The weights of two iron balls are $3.5 \text{ kg}$ and $7.5 \text{ kg}$. What is the percentage weight of the first ball with respect to the second ball?

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