The work done during reversible isothermal ex | vedclass

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(A) For a reversible isothermal expansion,the work done is given by the formula:$W = -2.303 \ nRT \log \frac{P_i}{P_f}$Given:$n = 1 \ mol$$R = 2.0 \ c

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$-413.14 \ calories$

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(A) For a reversible isothermal expansion,the work done is given by the formula:$W = -2.303 \ nRT \log \frac{P_i}{P_f}$Given:$n = 1 \ mol$$R = 2.0 \ cal \ K^{-1} \ mol^{-1}$$T = 25^{\circ}C = 298 \ K$$P_i = 20 \ atm$$P_f = 10 \ atm$Substituting the values:$W = -2.303 	imes 1 	imes 2.0 	imes 298 	imes \log \frac{20}{10}$$W = -2.303 	imes 2.0 	imes 298 	imes \log 2$$W = -2.303 	imes 596 	imes 0.3010$$W \approx -413.14 \ calories$

The work done during reversible isothermal expansion of one mole of hydrogen gas at $25^{\circ}C$ from a pressure of $20 \ atm$ to $10 \ atm$ is
(Given $R = 2.0 \ cal \ K^{-1} \ mol^{-1}$)

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The work done during reversible isothermal expansion of one mole of hydrogen gas at $25^{\circ}C$ from a pressure of $20 \ atm$ to $10 \ atm$ is(Given $R = 2.0 \ cal \ K^{-1} \ mol^{-1}$)