The work done in placing a charge of $8 \times 10^{-18} \, C$ on a condenser of capacity $100 \, \mu F$ is:

If the charge on a capacitor is increased by $2 \ C$, the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $C$)

The energy of a charged capacitor is given by the expression ($q$ = charge on the conductor and $C$ = its capacity).

$A$ fully charged capacitor has a capacitance $C$. It is discharged through a small coil of resistance wire,embedded in a block of specific heat $s$ and mass $m$ under thermally isolated conditions. If the temperature of the block is raised by $\Delta T$,the potential difference $V$ across the capacitor initially is

$A$ parallel plate capacitor has a plate separation $d$ and plate area $A$. If it is charged to a potential $V$ and then disconnected from the battery,calculate the work done in increasing the separation between the plates to $2d$.

If the energy density in a parallel plate capacitor is given as $1.8 \times 10^{-9} \ J/m^3$,then the value of the electric field in the region between the plates is ....... $NC^{-1}$. (Given: $\epsilon_0 = 9 \times 10^{-12} \ C^2/N \cdot m^2$)