The work function for a metal is 4 , eV. To e | vedclass

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(D) The photoelectric equation is given by $h
u = \Phi + KE$,where $\Phi$ is the work function and $KE$ is the kinetic energy.For zero velocity,$KE =

Vedclass · Accepted Answer

$3100$

Vedclass · Answer

(D) The photoelectric equation is given by $h
u = \Phi + KE$,where $\Phi$ is the work function and $KE$ is the kinetic energy.For zero velocity,$KE = 0$,so $h
u = \Phi$.Given $\Phi = 4 \, eV$,we have $h
u = 4 \, eV$.Using the relation $\lambda = \frac{hc}{\Phi}$,where $hc \approx 12400 \, eV \cdot \mathring{A}$:$\lambda = \frac{12400 \, eV \cdot \mathring{A}}{4 \, eV} = 3100 \, \mathring{A}$.Alternatively,using constants: $\lambda = \frac{6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{4 	imes 1.602 	imes 10^{-19}} \approx 3100 \, \mathring{A}$.Hence,the correct option is $D$.

The work function for a metal is $4 \, eV$. To emit a photo electron of zero velocity from the surface of the metal,the wavelength of incident light should be : ................ $\mathring{A}$

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