The zeros of p(x) = 2 + x - x^{2} are....... | vedclass

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(A) To find the zeros of the polynomial $p(x) = 2 + x - x^{2}$,we set $p(x) = 0$.$2 + x - x^{2} = 0$Rearranging the terms in standard form $ax^{2} + b

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$-1$ and $2$

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(A) To find the zeros of the polynomial $p(x) = 2 + x - x^{2}$,we set $p(x) = 0$.$2 + x - x^{2} = 0$Rearranging the terms in standard form $ax^{2} + bx + c = 0$:$-x^{2} + x + 2 = 0$Multiplying by $-1$ to simplify:$x^{2} - x - 2 = 0$Now,factor the quadratic equation by splitting the middle term:$x^{2} - 2x + x - 2 = 0$$x(x - 2) + 1(x - 2) = 0$$(x - 2)(x + 1) = 0$Setting each factor to zero:$x - 2 = 0 \implies x = 2$$x + 1 = 0 \implies x = -1$Thus,the zeros are $-1$ and $2$.

The zeros of $p(x) = 2 + x - x^{2}$ are.......

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