There are $m$ men and $2$ women participating in a chess tournament. Each participant plays $2$ games with every other participant. If the number of games played by the men between themselves exceeds the number of games played between the men and the women by $84$,then the value of $m$ is

  • A
    $12$
  • B
    $11$
  • C
    $9$
  • D
    $7$

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