There are 6 items in column A and 6 items in | vedclass

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(A) The $1^{	ext{st}}$ item in column $A$ can be matched with any of the $6$ items in column $B$.The $2^{	ext{nd}}$ item in column $A$ can be matche

Vedclass · Accepted Answer

$720$

Vedclass · Answer

(A) The $1^{	ext{st}}$ item in column $A$ can be matched with any of the $6$ items in column $B$.The $2^{	ext{nd}}$ item in column $A$ can be matched with any of the remaining $5$ items in column $B$.The $3^{	ext{rd}}$ item in column $A$ can be matched with any of the remaining $4$ items in column $B$.The $4^{	ext{th}}$ item in column $A$ can be matched with any of the remaining $3$ items in column $B$.The $5^{	ext{th}}$ item in column $A$ can be matched with any of the remaining $2$ items in column $B$.The $6^{	ext{th}}$ item in column $A$ can be matched with the last remaining $1$ item in column $B$.Therefore,the total number of possible ways to match the items is given by the permutation of $6$ items,which is $6! = 6 	imes 5 	imes 4 	imes 3 	imes 2 	imes 1 = 720$.

There are $6$ items in column $A$ and $6$ items in column $B$. $A$ student is asked to match each item in column $A$ with an item in column $B$. How many possible (correct or incorrect) answers are there to this question?

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