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(C) According to the fundamental principle of counting,if an event can occur in $m$ ways and another independent event can occur in $n$ ways,then the

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$3600$

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(C) According to the fundamental principle of counting,if an event can occur in $m$ ways and another independent event can occur in $n$ ways,then the total number of ways the two events can occur is $m 	imes n$.For the given $6$ questions:- The $1^{st}$ question has $3$ choices.- The $2^{nd}$ question has $3$ choices.- The $3^{rd}$ question has $4$ choices.- The $4^{th}$ question has $4$ choices.- The $5^{th}$ question has $5$ choices.- The $6^{th}$ question has $5$ choices.Total number of sequences of answers $= 3 	imes 3 	imes 4 	imes 4 	imes 5 	imes 5 = 3600$.

There are $6$ multiple choice questions in an examination. How many sequences of answers are possible,if the first $2$ questions have $3$ choices each,the next $2$ have $4$ choices each,and the last $2$ have $5$ choices each?

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