There are 5 white,7 red,4 black and 2 blue id | vedclass

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(A) Total number of balls = $5 + 7 + 4 + 2 = 18$.Number of white balls = $5$.Number of black balls = $4$.Number of balls that are neither white nor bl

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$1/2$

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(A) Total number of balls = $5 + 7 + 4 + 2 = 18$.Number of white balls = $5$.Number of black balls = $4$.Number of balls that are neither white nor black = Total balls - (White balls + Black balls) = $18 - (5 + 4) = 18 - 9 = 9$.The balls that are neither white nor black are the red and blue balls,which are $7 + 2 = 9$.Probability = $\frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{9}{18} = \frac{1}{2}$.

There are $5$ white,$7$ red,$4$ black and $2$ blue identical balls in a box. One ball is selected at random from the box. Find the probability that the selected ball is neither white nor black.

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