There are certain types of stars called varia | vedclass

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(B) The relationship between the apparent magnitude $(m)$ and the luminosity $(l)$ of a star is given by the formula: $m_2 - m_1 = -2.5 \log_{10} \lef

Vedclass · Accepted Answer

-$1.5$

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(B) The relationship between the apparent magnitude $(m)$ and the luminosity $(l)$ of a star is given by the formula: $m_2 - m_1 = -2.5 \log_{10} \left( \frac{l_2}{l_1} ight)$.Given that the star quadruples its light output,we have $\frac{l_2}{l_1} = 4$.Substituting this value into the formula:$m_2 - m_1 = -2.5 \log_{10}(4)$.Since $\log_{10}(4) = 2 \log_{10}(2) \approx 2 	imes 0.3010 = 0.6020$.Therefore,$m_2 - m_1 = -2.5 	imes 0.6020 = -1.505 \approx -1.5$.Thus,the magnitude changes by $-1.5$.

There are certain types of stars called variable stars which undergo periodic changes in their light output. If such a star quadruples its light output,how much does its magnitude change?

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