There are four complexes of Ni. Select the co | vedclass

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(D) Paramagnetic complexes are attracted by a magnetic field.$1$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pair

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$II$ and $IV$

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(D) Paramagnetic complexes are attracted by a magnetic field.$1$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons. It is diamagnetic.$2$. $[NiCl_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $Cl^-$ is a weak field ligand,no pairing occurs. It has $2$ unpaired electrons,so it is paramagnetic.$3$. $[Ni(CO)_4]$: $Ni$ is $3d^8 4s^2$. $CO$ is a strong field ligand,causing pairing. It is diamagnetic.$4$. $[Ni(H_2O)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. $H_2O$ is a weak field ligand,no pairing occurs. It has $2$ unpaired electrons,so it is paramagnetic.Thus,complexes $(II)$ and $(IV)$ are paramagnetic and will be attracted by a magnetic field.

There are four complexes of $Ni$. Select the complex(es) which will be attracted by a magnetic field:
$(I) \ [Ni(CN)_4]^{2-}, \ (II) \ [NiCl_4]^{2-}, \ (III) \ [Ni(CO)_4]$
$(IV) \ [Ni(H_2O)_6]^{2+}$

Similar Questions

The complex(es),which can exhibit the type of isomerism shown by $[Pt(NH_3)_2 Br_2]$,is(are) [en $= H_2 NCH_2 CH_2 NH_2$ ]
$(A)$ $[Pt(en)(SCN)_2]$
$(B)$ $[Zn(NH_3)_2 Cl_2]$
$(C)$ $[Pt(NH_3)_2 Cl_4]$
$(D)$ $[Cr(en)_2(H_2 O)(SO_4)]^{+}$

In $[Cr(C_2O_4)_3]^{3-}$,the isomerism shown is :-

Which among the following is a paramagnetic complex?
$($At. No. $Mo = 42, Pt = 78)$

Which of the following ions has the highest magnetic moment?

Indicate the types of isomerism exhibited by the following complexes and draw the structures for these isomers:
$(i)$ $K[Cr(H_2O)_2(C_2O_4)_2]$
$(ii)$ $[Co(en)_3]Cl_3$
$(iii)$ $[Co(NH_3)_5(NO_2)](NO_3)_2$
$(iv)$ $[Pt(NH_3)(H_2O)Cl_2]$

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There are four complexes of $Ni$. Select the complex(es) which will be attracted by a magnetic field:$(I) \ [Ni(CN)_4]^{2-}, \ (II) \ [NiCl_4]^{2-}, \ (III) \ [Ni(CO)_4]$$(IV) \ [Ni(H_2O)_6]^{2+}$