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(D) Let the capacitance of the air-filled capacitor be $C$. Its charge is $Q = CV$.Since the capacitors are identical,the capacitance of the dielectri

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$\frac{V}{K+1}$

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(D) Let the capacitance of the air-filled capacitor be $C$. Its charge is $Q = CV$.Since the capacitors are identical,the capacitance of the dielectric-filled capacitor is $C' = KC$.When the two capacitors are connected in parallel,the total charge $Q_{total}$ is conserved.$Q_{total} = Q_1 + Q_2 = 0 + CV = CV$.The equivalent capacitance of the parallel combination is $C_{eq} = C + KC = C(1+K)$.The common potential $V'$ is given by the formula $V' = \frac{Q_{total}}{C_{eq}}$.Substituting the values,we get $V' = \frac{CV}{C(1+K)}$.Therefore,$V' = \frac{V}{1+K}$.

There are two identical capacitors. The first one is uncharged and filled with a dielectric of constant $K$,while the second one is charged to potential $V$ and has air between its plates. If the two capacitors are joined in parallel,the common potential will be:

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