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(B) The force required to move the plate is given by Newton's law of viscosity: $F = \eta A \frac{dv}{dy}$.Given values:Area $A = 100 	ext{ cm}^2 = 1

Vedclass · Accepted Answer

$0.7$

Vedclass · Answer

(B) The force required to move the plate is given by Newton's law of viscosity: $F = \eta A \frac{dv}{dy}$.Given values:Area $A = 100 	ext{ cm}^2 = 100 	imes 10^{-4} 	ext{ m}^2 = 10^{-2} 	ext{ m}^2$.Gap $dy = 1 	ext{ mm} = 10^{-3} 	ext{ m}$.Velocity $v = 7 	ext{ cm/s} = 0.07 	ext{ m/s}$.Coefficient of viscosity $\eta = 1.0 	ext{ kg/(m} \cdot 	ext{s)}$.Substituting these values into the formula:$F = 1.0 	imes 10^{-2} 	imes \frac{0.07}{10^{-3}}$$F = 1.0 	imes 10^{-2} 	imes 70$$F = 0.7 	ext{ N}$.Therefore,the required force is $0.7 	ext{ N}$.

There is a $1$ $mm$ thick layer of glycerine between a flat plate of area $100$ $cm^2$ and a big fixed plate. If the coefficient of viscosity of glycerine is $1.0$ $kg/(m \cdot s)$,then what force in $N$ is required to move the plate with a velocity of $7$ $cm/s$?

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