There is a frill of 20 bulbs connected in ser | vedclass

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(A) The light will increase.In a series circuit,the total resistance $R$ is the sum of the resistances of individual bulbs $(R = R_1 + R_2 + ... + R_{

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Increase

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(A) The light will increase.In a series circuit,the total resistance $R$ is the sum of the resistances of individual bulbs $(R = R_1 + R_2 + ... + R_{20})$.The power consumed by the circuit is given by the formula $P = \frac{V^2}{R}$,where $V$ is the supply voltage and $R$ is the total resistance.When one bulb is removed (or fused),the total resistance of the circuit decreases because there are now only $19$ bulbs in series.Since the power $P$ is inversely proportional to the resistance $R$ $(P \propto \frac{1}{R})$,a decrease in total resistance leads to an increase in the total power consumed by the remaining bulbs.Therefore,the brightness of the light in the room will increase.

There is a frill of $20$ bulbs connected in series in a room. One bulb gets fused. The remaining $19$ are again joined in series and connected to the same supply. Will the light increase or decrease in the room?

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