There is an air-filled 1,pF parallel plate ca | vedclass

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(B) The capacitance of an air-filled parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d} = 1\,pF$.When the plate separation is doubled

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$4$

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(B) The capacitance of an air-filled parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d} = 1\,pF$.When the plate separation is doubled $(d' = 2d)$ and the space is filled with a dielectric material (wax) of constant $K$,the new capacitance is $C' = \frac{K \varepsilon_0 A}{d'}$.Substituting $d' = 2d$,we get $C' = \frac{K \varepsilon_0 A}{2d} = \frac{K}{2} \left( \frac{\varepsilon_0 A}{d} ight) = \frac{K}{2} C$.Given $C' = 2\,pF$ and $C = 1\,pF$,we have $2 = \frac{K}{2} 	imes 1$.Therefore,$K = 4$.

There is an air-filled $1\,pF$ parallel plate capacitor. When the plate separation is doubled and the space is filled with wax,the capacitance increases to $2\,pF$. The dielectric constant of wax is

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