(B) Graphite is thermodynamically the most stable allotrope of carbon. That is why $\Delta_fH^o$ (graphite) is taken as $0 \ kJ \ mol^{-1}$.$\Delta_fH

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(B) Graphite is thermodynamically the most stable allotrope of carbon. That is why $\Delta_fH^o$ (graphite) is taken as $0 \ kJ \ mol^{-1}$.$\Delta_fH^o$ (diamond) $= +1.90 \ kJ \ mol^{-1}$$\Delta_fH^o$ (fullerene) $= +38.1 \ kJ \ mol^{-1}$Since the standard enthalpy of formation of graphite is the lowest (zero),it is the most stable form.