Thiosulphate reacts differently with iodine and bromine in the reactions given below:
$2 S_2 O_3^{2-} + I_2 \rightarrow S_4 O_6^{2-} + 2 I^{-}$
$S_2 O_3^{2-} + 4 Br_2 + 5 H_2 O \rightarrow 2 SO_4^{2-} + 8 Br^{-} + 10 H^{+}$
Which of the following statements justifies the above dual behaviour of thiosulphate?
$2 S_2 O_3^{2-} + I_2 \rightarrow S_4 O_6^{2-} + 2 I^{-}$
$S_2 O_3^{2-} + 4 Br_2 + 5 H_2 O \rightarrow 2 SO_4^{2-} + 8 Br^{-} + 10 H^{+}$
Which of the following statements justifies the above dual behaviour of thiosulphate?
- ABromine undergoes oxidation and iodine undergoes reduction by iodine in these reactions
- BThiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions
- CBromine is a stronger oxidant than iodine
- DBromine is a weaker oxidant than iodine
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Match each of the reactions given in Column $I$ with the corresponding product$(s)$ given in Column $II$.
Column $I$ Column $II$ $(A)$ $Cu + \text{dil } HNO_3$ $(p)$ $NO$ $(B)$ $Cu + \text{conc } HNO_3$ $(q)$ $NO_2$ $(C)$ $Zn + \text{dil } HNO_3$ $(r)$ $N_2O$ $(D)$ $Zn + \text{conc } HNO_3$ $(s)$ $Cu(NO_3)_2$ $(t)$ $Zn(NO_3)_2$
| Column $I$ | Column $II$ |
| $(A)$ $Cu + \text{dil } HNO_3$ | $(p)$ $NO$ |
| $(B)$ $Cu + \text{conc } HNO_3$ | $(q)$ $NO_2$ |
| $(C)$ $Zn + \text{dil } HNO_3$ | $(r)$ $N_2O$ |
| $(D)$ $Zn + \text{conc } HNO_3$ | $(s)$ $Cu(NO_3)_2$ |
| $(t)$ $Zn(NO_3)_2$ |
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DifficultTS EAMCET 2018
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