This is the position-time graph of a mass on | vedclass

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(A) At the instant indicated by the dashed line,the particle is at its negative extreme position $(x = -A)$.At the extreme position,the velocity of th

Vedclass · Accepted Answer

Velocity is zero,force is to the right

Vedclass · Answer

(A) At the instant indicated by the dashed line,the particle is at its negative extreme position $(x = -A)$.At the extreme position,the velocity of the particle is zero $(v = 0)$.The restoring force in a spring is given by $F = -kx$. Since the particle is at $x = -A$,the force is $F = -k(-A) = +kA$.$A$ positive force indicates that the force is directed towards the positive direction (to the right).Therefore,the velocity is zero and the force is to the right.

This is the position-time graph of a mass on a spring. What can you say about the velocity and force at the instant indicated by the dashed line? (Positive direction is to the right.)

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