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(D) The sum of the ages of $5$ members $3$ $years$ ago was $5 	imes 17 = 85$ $years$.The sum of the present ages of these $5$ members is $85 + (5 	i

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(D) The sum of the ages of $5$ members $3$ $years$ ago was $5 	imes 17 = 85$ $years$.The sum of the present ages of these $5$ members is $85 + (5 	imes 3) = 85 + 15 = 100$ $years$.Currently,there are $6$ members in the family (including the baby),and the average age is still $17$ $years$.The sum of the present ages of all $6$ members is $6 	imes 17 = 102$ $years$.The age of the baby is the difference between the sum of the ages of $6$ members and the sum of the ages of the $5$ original members:Age of the baby $= 102 - 100 = 2$ $years$.

Three $years$ ago,the average age of a family of $5$ members was $17$ $years$. With the birth of a new baby,the average age of the family remains the same even today. Find the age of the baby (in $years$).

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