Three blocks of different masses connected wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total mass of the system is $M = 2 	ext{ kg} + 8 	ext{ kg} + 12 	ext{ kg} = 22 	ext{ kg}$.The acceleration of the system is $a = F / M = F

Vedclass · Accepted Answer

$1:5$

Vedclass · Answer

(A) The total mass of the system is $M = 2 	ext{ kg} + 8 	ext{ kg} + 12 	ext{ kg} = 22 	ext{ kg}$.The acceleration of the system is $a = F / M = F / 22$.$T_1$ is the tension in the string pulling the $12 	ext{ kg}$ block. Thus, $T_1 = 12 	imes a = 12 	imes (F / 22) = 6F / 11$.$T_2$ is the tension in the string pulling the $12 	ext{ kg}$ and $8 	ext{ kg}$ blocks. Thus, $T_2 = (12 + 8) 	imes a = 20 	imes (F / 22) = 10F / 11$.The ratio of tensions $T_1$ to $T_2$ is $T_1 / T_2 = (6F / 11) / (10F / 11) = 6 / 10 = 3 / 5$.Given the options provided, there appears to be a discrepancy with standard physics calculations. However, if we re-examine the diagram, $T_1$ pulls the $12 	ext{ kg}$ block and $T_2$ pulls the $8 	ext{ kg}$ and $2 	ext{ kg}$ blocks (if $T_2$ were between $2$ and $8$), the ratio would differ. Based on the provided image, the calculated ratio is $3:5$. Since this is not an option, the question or options may be flawed.

Three blocks of different masses connected with inextensible strings are pulled by a force $F$ on a frictionless surface as shown in the figure. The ratio of tensions $T_1$ to $T_2$ is

Similar Questions

Four blocks are connected as shown in the figure on a horizontal frictionless surface. If $m_1 = m_2 = m_3 = m_4 = m$,then the ratio $T_3 / T_4$ will be:

For the given figure,what will be the contact force applied by the $6 \ kg$ block on the $4 \ kg$ block? ............ $N$

An elevator accelerates upwards at a constant rate. $A$ uniform string of length $L$ and mass $m$ supports a small block of mass $M$ that hangs from the ceiling of the elevator. The tension at distance $l$ from the ceiling is $T$. The acceleration of the elevator is

An elevator of mass $m$ is connected to a rope which pulls the elevator up with a maximum acceleration equal to $a$. If the maximum bearable tension in the rope is $T$,then for a safe journey the minimum diameter of the rope is $[g=$ acceleration due to gravity$]$

$A$ mass $1\, kg$ is suspended by a thread. It is
$(i)$ lifted up with an acceleration $4.9\, m/s^2$
$(ii)$ lowered with an acceleration $4.9\, m/s^2$.
The ratio of the tensions is

Vedclass Test Series

Exam Paper Generator

Online Exam Module