Three brothers divided ₹ 1620 among themselve | vedclass

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(B) Let the shares of the three brothers be $A$,$B$,and $C$ respectively.According to the problem,the total amount is $A + B + C = 1620$.We are given

Vedclass · Accepted Answer

$450$

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(B) Let the shares of the three brothers be $A$,$B$,and $C$ respectively.According to the problem,the total amount is $A + B + C = 1620$.We are given that the share of the second brother $B$ is $\frac{5}{13}$ of the sum of the shares of the other two,i.e.,$B = \frac{5}{13}(A + C)$.Substituting $(A + C)$ from the total sum equation: $(A + C) = 1620 - B$.Now,substitute this into the given condition:$B = \frac{5}{13}(1620 - B)$$13B = 5(1620 - B)$$13B = 8100 - 5B$$13B + 5B = 8100$$18B = 8100$$B = \frac{8100}{18} = 450$.Therefore,the share of the second brother is ₹ $450$.

Three brothers divided ₹ $1620$ among themselves in such a way that the share of the second brother is equal to $\frac{5}{13}$ of the share of the other two combined. What is the share of the second brother?

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