Three capacitors are connected to a $D.C.$ source of $100 \; V$ as shown in the figure. If the charges accumulated on plates $a, b, c, d, e,$ and $f$ are ${q_a}, {q_b}, {q_c}, {q_d}, {q_e},$ and ${q_f}$ respectively,then:

  • A
    ${q_b} + {q_d} + {q_f} = \frac{100}{9} \; C$
  • B
    ${q_b} + {q_d} + {q_f} = 0$
  • C
    ${q_a} + {q_c} + {q_e} = 50 \; C$
  • D
    ${q_b} = {q_d} = {q_f}$

Explore More

Similar Questions

The figure shows a network of five capacitors connected to a supply voltage '$V$'. The equivalent capacitance and the energy stored in the network are respectively:

In the connections shown in the adjoining figure,the equivalent capacitance between $A$ and $B$ will be......$\mu F$.

Four capacitors,each of capacitance $8 \mu F$,are connected as shown in the figure. The equivalent capacitance between points $A$ and $B$ is: (in $\mu F$)

In the given network, the value of $C$, so that an equivalent capacitance between points $A$ and $B$ is $3 \mu F$, is

The effective capacitances of two capacitors are $3\,\mu F$ and $16\,\mu F$,when they are connected in series and parallel respectively. The capacitances of the two capacitors are:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo