Three capacitors each of $4\,\mu F$ are to be connected in such a way that the effective capacitance is $6\,\mu F$. This can be done by connecting them:

  • A
    all in series
  • B
    all in parallel
  • C
    two in parallel and one in series
  • D
    two in series and one in parallel

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Similar Questions

From the circuit given below, the capacitance between terminals $A$ and $B$ is . . . . . . $\mu\text{F}$. (Take $C_1 = C_2 = C_3 = 1\text{ }\mu\text{F}$ and $C_4 = 2\text{ }\mu\text{F}$.)

In the circuit diagram shown in the adjoining figure,the resultant capacitance between $P$ and $Q$ is ........ $\mu F$.

Two parallel plate capacitors are connected in series. Each capacitor has a plate area $A$ and a separation $d$ between the plates. The dielectric constants of the media between their plates are $2$ and $4$. The separation between the plates of a single air capacitor of plate area $A$ which effectively replaces the combination is:

The equivalent capacitance of the system shown in the following circuit is $...........\mu F$.

What is series connection of capacitors? And what is parallel connection of capacitors?

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