Three capacitors of capacitance $1\ \mu F$,$2\ \mu F$,and $3\ \mu F$ are connected in series,and a potential difference of $11\ V$ is applied across the combination. The potential difference across the plates of the $1\ \mu F$ capacitor is......$V$.

Three condensers of capacities $C_{1}, C_{2}, C_{3}$ are connected in series with a source of e.m.f. $V$. The potentials across the three condensers are in the ratio of

Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then:

What is the equivalent capacitance between the points $P$ and $Q$ in the combination of capacitors shown in the figure (in $\mu F$)?

Three capacitors $C_1$,$C_2$,and $C_3$ are connected in parallel,and their equivalent capacitance is $12$ units. Given $C_1 \cdot C_2 \cdot C_3 = 48$ units. When $C_1$ and $C_2$ are connected in parallel,their equivalent capacitance is $6$ units. Find the individual capacitances $C_1, C_2, C_3$.

The equivalent capacitance between $A$ and $B$ in the circuit given below is.....$\mu F$