Three charges 2q, -q and -q are located at th | vedclass

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(B) Let $r$ be the distance from each vertex to the centre of the equilateral triangle.The electric potential $V$ at the centre due to the three charg

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the field is non-zero but potential is zero.

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(B) Let $r$ be the distance from each vertex to the centre of the equilateral triangle.The electric potential $V$ at the centre due to the three charges is the algebraic sum of the potentials due to each charge:$V = V_{2q} + V_{-q} + V_{-q} = \frac{k(2q)}{r} + \frac{k(-q)}{r} + \frac{k(-q)}{r} = \frac{k}{r} (2q - q - q) = 0$.Thus,the potential at the centre is zero.For the electric field,the field due to the two $-q$ charges at the base will have a resultant pointing towards the base,while the field due to the $2q$ charge at the top will point away from it (downwards). Since the magnitudes of these fields do not cancel out,the net electric field at the centre is non-zero.

Three charges $2q, -q$ and $-q$ are located at the vertices of an equilateral triangle. At the centre of the triangle,

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